By passing vapours of phenol over heated $zinc$ dust will produce :

Phenol $\xrightarrow{Zn \, \text{dust}} X$ $\xrightarrow[Anhyd. \, AlCl_3]{CH_3Cl} Y$ $\xrightarrow{\text{Alkaline } KMnO_4} Z$. In the above reaction,what is $Z$?

An organic compound with the molecular formula $C_6H_6O$ dissolves in $NaOH$, gives a characteristic colour with neutral $FeCl_3$ and on treatment with bromine water gives a tri-bromo derivative. Which is that compound among the following?

Explain why the $-OH$ group in phenols is more strongly held as compared to the $-OH$ group in alcohols?

The Reimer-Tiemann reaction introduces an aldehyde group onto the aromatic ring of phenol,ortho to the hydroxyl group. This reaction involves electrophilic aromatic substitution. This is a general method for the synthesis of substituted salicylaldehydes as depicted below.
$1.$ Which one of the following reagents is used in the above reaction?
$A.$ aq. $NaOH + CH_3Cl$
$B.$ aq. $NaOH + CH_2Cl_2$
$C.$ aq. $NaOH + CHCl_3$
$D.$ aq. $NaOH + CCl_4$
$2.$ The electrophile in this reaction is
$A.$ $:CHCl$
$B.$ $^{+}CHCl_2$
$C.$ $:CCl_2$
$D.$ $CCl_3^{-}$
$3.$ The structure of the intermediate $I$ is
(See provided image for structures $A$,$B$,$C$,$D$)
Give the answer for questions $1, 2$ and $3.$

The major products of Reimer-Tiemann reaction and Kolbe reaction are respectively: